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chapter 1 • introduction
1.1 a gas at 20°c may be rarefied if it contains less than 1012 molecules per mm3. if avogadro’s number is 6.023e23 molecules per mole, what air pressure does this represent? solution: the mass of one molecule of air may be computed as m= molecular weight 28.97 mol −1 = = 4.81e−23 g avogadro’s number 6.023e23 molecules/g ⋅ mol
then the density of air containing 1012 molecules per mm3 is, in si units,
molecules öæ g æ ö ρ = ç 1012 ÷ç 4.81e−23 ÷ 3 molecule ø mm è øè g kg = 4.81e−11 = 4.81e−5 3 3 mm m
finally, from the perfect gas law, eq. (1.13), at 20°c = 293 k, we obtain the pressure:
kg ö æ m2 ö æ p = ρ rt = ç 4.81e−5 3 ÷ ç 287 2 ÷ (293 k) = 4.0 pa αns. m øè s ⋅k ø è
1.2 the earth’s atmosphere can be modeled as a uniform layer of air of thickness 20 km and average density 0.6 k
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向豆丁求助：有没有Fluid?
