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[工学]电路基础第三版Alexander and Sadiku著 课后题答案chapter 11.pdf
- [工学]电路基础第三版Alexander and Sadiku著 课后题答案chapter 11
chapter 11, problem 1. if v(t) = 160 cos 50t v and i(t) = –20 sin(50t – 30°) a, calculate the instantaneous power and the average power.
chapter 11, solution 1.
v( t ) = 160 cos(50t ) i( t ) = -20 sin(50t − 30°) = 2 cos(50t − 30° + 180° − 90°) i( t ) = 20 cos(50t + 60°) p( t ) = v( t ) i( t ) = (160)(20) cos(50t ) cos(50t + 60°) p( t ) = 1600 [ cos(100 t + 60°) + cos(60°) ] w p( t ) = 800 + 1600 cos(100t + 60°) w
1 1 vm i m cos(θ v − θi ) = (160)(20) cos(60°) 2 2 p = 800 w p=
proprietary material. © 2007 the mcgraw-hill companies, inc. all rights reserved. no part of this manual may be displayed, reproduced or distributed in any form or by any means, without the prior written permission
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[工学]电路基础第三版Alexander and Sadiku著 课后题答案chapter 13.pdf
- [工学]电路基础第三版Alexander and Sadiku著 课后题答案chapter 13
chapter 13, problem 1. for the three coupled coils in fig. 13.72, calculate the total inductance.
figure 13.72 for prob. 13.1. chapter 13, solution 1. for coil 1, l1 – m12 + m13 = 6 – 4 + 2 = 4
for coil 2, l2 – m21 – m23 = 8 – 4 – 5 = – 1 for coil 3, l3 + m31 – m32 = 10 + 2 – 5 = 7 lt = 4 – 1 + 7 = 10h or lt = l1 + l2 + l3 – 2m12 – 2m23 + 2m12 lt = 6 + 8 + 10 = 10h
chapter 13, problem 2. determine the inductance of the three series-connected inductors of fig. 13.73.
figure 13.73 for prob. 13.2. chapter 13, solution 2.
l = l1 + l2 + l3 + 2m12 – 2m23 –2m31 = 10 + 12 +8 + 2x6 – 2x6 –2x4 = 22h
proprietary material. © 2007 the mcgraw-hill companies, inc. all rights reserved. no part of this manual may be displayed, reproduced or distributed in any form or by any means, without the prior written permission of the publisher, or used
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C++ STL使用教程下载-Alexander版.pdf
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电路基础(第三版)Alexander_and_Sadiku著_课后题答案chapter_09.pdf
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Study Guide for The Iliad by Homer (Alexander Pope ....pdf
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英文传记中实义动词和短语动词汉译实践报告--以Alexander the Great_Journey.pdf
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《汉密尔顿传》(Alexander_Hamilton)_章节单词统计_带英文解释排版.pdf
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向豆丁求助：有没有Alexander?
